Answer:
m₁×m₂ = -1
m₁ = 3 and m₂ = -1/3
3×-1/3 = -1
-1 = -1
Hence proved, the given two lines are perpendicular.
Explanation:
You can prove that the two lines are perpendicular if the following condition holds true.
m₁×m₂ = -1
Where m₁ is the slope of line 1 and m₂ is slope of line 2
So first you have to find out the slope of each line.
You are given 2 equations
y = 3x + 5 eq. 1
6y + 2x = 1 eq. 2
You have to write these equations in slope-intercept form to find out their slopes.
The slope-intercept form is given by
y = mx + b
Comparing the general form with eq. 1
y = 3x + 5
We notice that the slope is m₁ = 3
Now convert the eq. 2 into slope-intercept form
6y + 2x = 1 eq. 2
6y = -2x + 1
y = (-2x + 1)/6
y = -1/3x + 1/6 eq. 2
Comparing the general form with eq. 2
y = -1/3x + 1/6
We notice that the slope is m₂ = -1/3
Now we have slopes of both lines so let us test whether they are perpendicular or not
m₁×m₂ = -1
m₁ = 3 and m₂ = -1/3
3×-1/3 = -1
-1 = -1
Hence proved, the given two lines are perpendicular.