Question

The width of rectangle is 7 less than twice the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the rectangle?

Answer 1

29.49 square inches

Explanation:

Let the length of the rectangle be x inches

Therefore, width = (2x - 7) inches

Perimeter of rectangle =2( length + width)

therefore,

43.6 = 2 ( x + 2x - 7)

43.6/2 = 2 ( 3x - 7)

21.8 = 6x - 14

21.8 + 14 = 6x

6x = 35.8

x = 35.8/6

x = 5.97 inches

Length = 5.97 inches

width = 2*5.97-7 =11.94 - 7 = 4. 94 inches

Area of rectangle

= Length * width

= 5.97*4.94

=29.4918

= 29.49 square inches