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How many grams of krypton gas would occupy 1.34L at STP?

User Marialisa
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1 Answer

2 votes

Answer:

5.01 g

Step-by-step explanation:

At STP means at standard temperature and pressure, this is when the pressure is at 1 atm and temperature is at 273 K. At this point, the volume is 22.4 L for 1 mole of any ideal gas at a temperature equal to 273.15 K and a pressure equal to 1.00 atm

The molar mass of krypton as gotten from the periodic table is 83.8 g/mol. At STP, an ideal gas occupies 22.4 L/mol. Therefore, the grams that 1.3 L of krypton gas would occupy is:


mass=(1mol)/(22.4L) *(83.8g)/(1mol) *1.34L=5.01g

User Mikbal
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