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How many ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

User Lashanna
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1 Answer

7 votes

Answer: 127.5ml

Step-by-step explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:


n_1M_1V_1=n_2M_2V_2

where,


n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is
HNO_3


n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:


n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.75M\\V_2=85mL

Putting values in above equation, we get:


1* 0.5* V_1=1* 0.75* 85\\\\V_1=127.5mL

Thus 127.5 ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

User Niieani
by
8.3k points
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