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Let (-3,5) be a point on the terminal side of theta. Find the exact values of sin theta, secant theta, and tangent theta

Can someone please help me out with this? If possible, providing a diagram would be helpful!

1 Answer

4 votes

Answer:

Cosθ = 0.5145

Sinθ = 0.8575

Secθ = 1.9436

tanθ = 1.667

Explanation:

From the figure attached,

Point P(-3, 5) is on the terminal side and AB is the initial side of the angle PAB.

If m∠PAB = θ

AB =
\sqrt{(3)^(2)+(5)^(2)}

=
√(34)

= 5.831

Then Cosθ =
(AB)/(AP) =
(3)/(5.831)

Cosθ = 0.5145

Sinθ =
(PB)/(AP)

Sinθ =
(5)/(5.831)

Sinθ = 0.8575

Secθ =
\frac{1}{\text{Cos}\theta}

Secθ =
(1)/(0.5145)

Secθ = 1.944

tanθ =
(PB)/(AB)

tanθ =
(5)/(3)

tanθ = 1.667

Let (-3,5) be a point on the terminal side of theta. Find the exact values of sin-example-1
User Shigeo
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