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If a plant needs to make 12.6 g of glucose(c6h1206), how many grams of water are required?

User Gabby
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Answer: 7.6 g of water are required to make 12.6 g of glucose

Step-by-step explanation:

Moles is calculated by using the formula:


Moles=\frac{\text{Given mass}}{\text{Molar mass}}


{\text {moles of glucose}}=(12.6g)/(180g/mol)=0.07moles

The balanced chemical equation is:


6CO_2+6H_2O\rightarrow C_6H_(12)O_6+6O_2

According to stoichiometry:

1 mole of glucose is produced by = 6 moles of water

Thus 0.07 moles of glucose is produced by =
(6)/(1)* 0.07=0.42 moles of water

Mass of water required =
moles* {\text {Molar mass}}=0.42mol* 18g/mol=7.6g

Thus 7.6 g of water are required to make 12.6 g of glucose

User Oberlies
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