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You are required to prepare 500 ml of a 6.00 M solution of HNO3 from a stock solution of 12.0 M. Describe in detail how you would go about preparing this solution. Clearly state the volume of stock solution used, the glassware's used and the procedure. ​

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Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

Step-by-step explanation:

According to the dilution law,


C_1V_1=C_2V_2

where,


C_1 = concentration of stock solution = 12.0 M


V_1 = volume of stock solution = ?


C_2 = concentration of diluted solution= 6.00 M


V_2 = volume of diluted acid solution = 500 ml

Putting in the values we get:


12.0* V_1=6.00* 500


V_1=250ml

Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

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