Question

You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point. 2 lines connect and go up to the right and down to the right. The line that goes up to the right points to Ace, and the line that goes down to the right points to Not an ace. StartFraction 4 Over 52 EndFraction is above the lines, and StartFraction question mark Over 52 EndFraction is below the lines. Write the equation for the expected value. E(V) = 4 52 (a) + b 52 (c) a = b = c =

Answer 1

The equation for the expected value in this scenario is: E(V) = -4/52 * (a) + 48/52 * (b), where 'a' represents the gain of 9 points if the card is an ace, and 'b' represents the loss of 1 point if the card is not an ace. By evaluating this equation, the expected value for this game is approximately -0.154, which means that over the long term, you would expect to lose approximately 15 cents per game, on average.

Step-by-step explanation:

The equation for the expected value in this scenario is:

E(V) = − 4/52 * (a) + + 48/52 * (b)

where 'a' represents the gain of 9 points if the card is an ace, and 'b' represents the loss of 1 point if the card is not an ace.

In this case, a = 9 and b = -1, as mentioned in the question. Therefore, the equation can be simplified to:

E(V) = − 4/52 * 9 + + 48/52 * (-1)

By evaluating this equation, the expected value for this game is -0.154, which means that over the long term, you would expect to lose approximately 15 cents per game, on average.

Answer 2

1) A= 9
B= 48
C= -1

2) C.

3) B.

4) 12

Step-by-step explanation: