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How many moles of HCI are needed to prepare 8.0 liters of a 4.0 M solution of HCI?

0.5 mol HCL

32 mol HCI

12 mol HCL

2 mol HCI


1 Answer

3 votes

Answer: 32 mol HCI

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.


Molarity=(n)/(V_s)

where,

n = moles of solute


V_s = volume of solution in Liters

Now put all the given values in the formula of molarity, we get


4.0M=(moles)/(8.0L)


moles={4.0M* 8.0L}=32mol

Therefore, the moles of HCI needed to prepare 8.0 liters of a 4.0 M solution of HCI are 32.

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