Question

Find the perimeter of a rectangle with a length of 32 feet and a width of 56 feet

Answer 1

Hey!!!!

Here's your answer

Solution:

Length(l)=32 feet

Breadth(b)=56 feet

Now,

Perimeter of rectangle=2(l+b)

=2(32+56)

=2*88

=176

So the right answer is 176 feet

Hope it helps ...

Good luck on your assignment

Answer 2

Perimeter= 176

Explanation:

If one length is 32, then the length parallel to it, is also 32. Meaning the side lengths altogether equal 64. The width, is 56, so then the width parallel to it is also 56. This means the width of each equals 112 altogether.

64+112=176.

P= 176 feet