Question

You launch a water balloon. The function h=-0.08t^2+1.6t+2 models the height h (in feet) of the water balloon after t seconds. What is the initial height of the balloon?

Answer 1

The initial height of the balloon is 2 feet.

Explanation:

The height of the balloon in feet after t seconds is given by the following equation:

`h(t) = -0.08t^(2) + 1.6t + 2`

What is the initial height of the balloon?

This is h when t = 0, that is, h(0). So

`h(0) = -0.08*0^(2) + 1.6*0 + 2 = 2`

The initial height of the balloon is 2 feet.