95.5k views
2 votes
Neglecting air​ resistance, the distance s(t) in feet traveled by a freely falling object is given by the function s(t)=16t squared​, where t is time in seconds. The height of a certain tower is 986 feet. How long would it take an object to fall to the ground from the top of the​ building?

User Pedlar
by
6.2k points

2 Answers

3 votes

Answer:

7.85sec

Explanation:

Given that,

s(t)=16t squared​, where t is time in seconds. The height of a certain tower is 986 feet.

s(t) = 16t²

so when s = 986feet

16t² = 986 feet

t² = 986 / 16

t² = 61.625

t = √61.625

t= 7.85 seconds

User Ivg
by
6.4k points
6 votes

Answer: t = 7.85seconds

Explanation:

Given that :

Height of tower = 986 Feets

Function s(t) = 16t^2

To find the time t 8 in Seconds taken for an object to fall to the ground from the top of the​ building

16t^2 = 986

t^2 = 986/16

t ^2 = 61.625

Take the square root of both sides

t = sqrt(61.625)

t = 7.85seconds

User Vemul
by
7.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.