Question

On a coordinate plane, 2 exponential functions are shown. Function f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. Function g (x) approaches y = 0 in quadrant 1 and increases into quadrant 2.

Which function represents a reflection of f(x) = Three-eighths(4)x across the y-axis?


g(x) = NegativeThree-eighths (one-fourth) Superscript x

g(x) = Negative three-eighths(4)x

g(x) = Eight-thirds(4)-x

g(x) = Three-eighths(4)–x

Answer 1

D

Explanation:

Answer 2

`g(x)=f(-x)=(3)/(8)(4)^(-x)`

Explanation:

The pre-image is

`f(x)=(3)/(8)(4)^(x)`

To make a reflection across the y-axis, we need to apply the transformation

`(x,y) \implies (-x,y)`

Which give the function

`g(x)=f(-x)=(3)/(8)(4)^(-x)`

Therefore, the right answer is the last choice.