Question

One cylinder has a volume that is 8 cm' less than a of the volume of a second cylinder. If the first cylinder's volume is 216

cm? what is the correct equation and value of x, the volume of the second cylinder?
x+8-216; x = 182 cm
-8-2167 - 196 cm
coll
+8-216-238cm
col
-8-216
-256 cm
Nacks and otum
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Answer 1

The answer is D

Explanation:

Answer 2

Corrected Question

One cylinder has a volume that is 8cm less than 7/8 of the volume of a second cylinder. If the first cylinder’s volume is 216cm³, what is the correct equation and value of x, the volume of the second cylinder?

Answer:

The equation is:
`216=(7)/(8)x-8`

Volume of the second cylinder=
`256cm^3`

Explanation:

Volume of the first cylinder=
`216cm^3`

Let the volume of the second cylinder=x

7/8 of the volume of a second cylinder=
`(7)/(8)x`

8 less than 7/8 of the volume of a second cylinder=
`(7)/(8)x-8`

Therefore, the equation is:

`216=(7)/(8)x-8`

Next, we solve for x

`216=(7)/(8)x-8\\216+8=(7)/(8)x\\224=(7)/(8)x\\$Cross multiply\\7x=224*8\\Divide both sides by 7\\x=256cm^3`

The volume of the second cylinder is
`256cm^3`