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Suppose the sphere below with radius r has a surface area equal to 50 units². find the surface area of the sphere with twice the radius.

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Answer:


200$ unit^2

Explanation:

Surface Area of a Sphere
=4\pi r^2

Given that the surface area of a sphere is 50 units².

Then:


4\pi r^2 =50\\r^2=(50)/(4\pi)\\ r=\sqrt{(50)/(4\pi)}

If a sphere has twice the radius of the sphere above

Its radius,
r=2\sqrt{(50)/(4\pi)}

Therefore its Surface Area


=4\pi\left(2\sqrt{(50)/(4\pi)}\right)^2\\=4\pi*4*(50)/(4\pi)}\\\\=200 unit^2

User Torongo
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