Question

Simplify exponents please! need the answer immediately.

Answer 1

• 
  `(w^(6) )/(9 )`

Explanation:

Given

• 
  `(3^(-2)*k^(0)*w^(0) )/(w^(-6) )`

Remember :

• Any term raised to the power 0 is equal to 1

Solving

• 
  `(3^(-2) )/(w^(-6) )`
• 
  `(w^(6) )/(9)`

Answer 2

`\huge\boxed{\bf\:(w^(6))/(9)}`

Explanation:

`\frac{ 3 ^ { -2 } * k ^ { 0 } * w ^ { 0 } }{ w ^ { -6 } }`

Any number with 0 as its exponent will be equal to 1. So,

`(3^(-2) * 1 * 1)/(w^(-6))\\= (3^(-2))/(w^(6))`

Now,

`(3^(-2))/(w^(6))\\= 3^(-2)w^(6)`

Then,

`3^(-2)w^(6)\\= (1)/(3^(2))w^(6)\\= (1)/(9)w^(6)\\= \boxed{\bf\:(w^(6))/(9)}`

`\rule{150pt}{2pt}`