Answer:
v = 51.60 m/s
Step-by-step explanation:
To calculate the velocity of the Earth around the sun you use the following formula, which comes from the universal gravitational Law:

M_E: Earth's mass = 5.97*10^24 kg
r: distance between the Sun and the Earth = 149 600 000 km =m
G: Cavendish's constant = 6.674×10−11 m3⋅kg−1⋅s−2
You replace the values of G, M_E and r in the equation for v:

hence, the velocity of traslation of the Earth is 51.60 m/s