Question

1.What volume of 0.871 M oxalic acid contains 86.9 g of oxalic acid (H2C2O4)?

Answer 1

1.11 L

Step-by-step explanation:

Given data

• Molarity of the oxalic acid solution (M): 0.871 M

• Mass of oxalic acid (m): 86.9 g

Step 1: Calculate the moles corresponding to 86.9 g of oxalic acid

The molar mass of oxalic acid is 90.03 g/mol.

`86.9g * (1mol)/(90.03g) = 0.965 mol`

Step 2: Calculate the volume of a 0.871 M solution that contains 0.965 moles of oxalic acid

The molarity is equal to the moles of solute (n) divided by the volume of the solution (V).

`M = (n)/(V) \\V = (n)/(M) = (0.965mol)/(0.871 mol/L) =1.11 L`