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If the reaction of 5.87 moles of potassium with excess hydrobromic acid was able to produce 2.49 mol H2, what is the percent yield of hydrogen gas? (3 points) Unbalanced equation: K + HBr yields KBr +
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If the reaction of 5.87 moles of potassium with excess hydrobromic acid was able to produce 2.49 mol H2, what is the percent yield of hydrogen gas? (3 points)

Unbalanced equation: K + HBr yields KBr + H2

1. 14.6%
2. 29.2%
3. 42.4%
4. 84.8%

User Dr Nick Engerer
by
7.3k points

1 Answer

12 votes

Answer: 2. 29.2%

Step-by-step explanation:

User BBonifield
by
8.6k points
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