Answer:
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
P(x⁻>96) =0.0359
Explanation:
Explanation:-
Given sample size 'n' =10
mean of the Population = 90 words per minute
standard deviation of the Population =10 wpm
we will use formula
![Z = (x^(-)-mean )/((S.D)/(√(n) ) )](https://img.qammunity.org/2021/formulas/mathematics/college/5lcw58pjz9g1ychdlj4zteqg1cxhiab0gg.png)
Let X⁻ = 96
![Z = (96-90 )/((10)/(√(10) ) )](https://img.qammunity.org/2021/formulas/mathematics/college/ps191y9sr7w4o89gr009gmzlqvk0zr92k6.png)
Z = 1.898
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
![P(X^(-)>x^(-) ) = P(Z > z^(-) )](https://img.qammunity.org/2021/formulas/mathematics/college/tqxcx2wvpfljh2y6p9pis8nc8v7cnwlizk.png)
= 1- P( Z ≤z⁻)
= 1- P(Z<1.898)
= 1-(0.5 +A(1.898)
= 0.5 - A(1.898)
= 0.5 -0.4641 (From Normal table)
= 0.0359
Final answer:-
The probability that a random sample of 10 second grade students from
= 0.0359