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What is the number of moles of KF in a 29-gram sample of the compound?

A) 1.0 mol

B) 2.0 mol

C) 0.50 mol

D) 5.0 mol

2 Answers

7 votes

Answer:

C) 0.50 mol

Step-by-step explanation:

Hello,

In this case, we study this mole-mass relationship by using the molar mass of potassium fluoride (KF) which is 58.1 g/mol to compute the required number of moles in the 29-g sample as shown below:


n_(KF)=29gKF*(1molKF)/(58.1gKF) \\\\n_(KF)=0.50molKF

Therefore answer is C) 0.50 mol.

Best regards.

User LuckyStarr
by
4.8k points
4 votes

Answer:

C. 0.50 mol

Step-by-step explanation:

Number of mole= mass /molar mass

Mass of KF is given as 29g

The molar mass of KF= 39+19= 58g/mol

No of mole= mass/ molar mass

= 29g/58g/mol

1/2 mol= 0.5 mol

User RobertBaron
by
4.7k points