98.9k views
0 votes
The first three towers in a sequence are shown. The nth tower is formed by stacking n blocks on top of an n times n square of blocks. How many blocks are in the 99th tower?

The first three towers in a sequence are shown. The nth tower is formed by stacking-example-1
User Rksh
by
8.5k points

1 Answer

1 vote

Answer:

The 99th tower contains 9900 blocks.

Explanation:

From the question given, we were told that the nth tower is formed by stacking n blocks on top of an n times n square of blocks. This implies that the number of blocks in n tower will be:

n + n²

Now let us use the diagram to validate the idea.

Tower 1:

n = 1

Number of blocks = 1 + 1² = 2

Tower 2:

Number of blocks = 2 + 2² = 6

Tower 3:

Number of blocks = 3 + 3² = 12

Using same idea, we can obtain the number of blocks in the 99th tower as follow:

Tower 99:

n = 99

Number of blocks = 99 + 99² = 9900

Therefore, the 99th tower contains 9900 blocks.

User Specto
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories