Question

To what Kelvin temperature must a balloon

be cooled if its original temperature

was 323 °C to cause a 2.85 L balloon shrink to 1.25 L?

Answer 1

`T_2=261.46\ K`

Step-by-step explanation:

It is given that,

Original temperature,
`T_1=323^(\circ)C=596.15\ K`

Original volume,
`V_1=2.85\ L`

We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.

According to Charles law, at constant pressure,
`V\propto T`

It would means,
`(V_1)/(V_2)=(T_1)/(T_2)`

T₂ = ?

`T_2=(V_2T_1)/(V_1)\\\\T_2=(1.25* 596.15)/(2.85)\\\\T_2=261.46\ K`

So, the new temperature is 261.46 K.