Question

Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiempo alcanzará el coche a la furgoneta? ¿A qué distancia se producirá el encuentro?

Answer 1

t = 0.33h = 1200s

x = 18.33 km

Step-by-step explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

`x=x_o+v_1t` (1)

xo = 10 km

v1 = 55km/h

car 2:

`x'=v_2t` (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

`x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=(x_o)/(v_2-v_1)`

`t=(10km)/(85km/h-55km/h)=0.33h*(3600s)/(1h)=1200s`

The position in which both cars coincides is:

`x=(55km/h)(0.33h)=18.33km`