Question

X^3+3y-xy' = 0

dy/dx = xy^3-xy

Answer 1

dy/dx = xy^3-xy =

y = ± √2 = ± 1.4142

x = 0

y = 0

Explanation:

Step 1 : Simplify y/d

Step 2 : See below

Step 3 : See below

Pulling out like terms

Trying to factor as a Difference of Squares

Answer:

y = ± √2 = ± 1.4142

x = 0

y = 0

Hope this helps.