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What are the minimum energies of the two oppositely directed gamma rays in a pet procedure?.

User Dorien
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1 Answer

10 votes

Answer:

0.51 1 MeV

Step-by-step explanation:

-mec2 is the rest energy of the electron (0.511 MeV)

-Pair production and triplet production are followed by the annihilation of the positron with a ‘free’ electron producing two annihilation quanta, most commonly with an energy of 0.511 MeV each and emitted at 180º from each other to satisfy conservation of energy, momentum and charge.

User Ideaztech
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