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How much energy is required to heat 250 grams of water from 20.0°C to 80.0°C? The heat capacity of water is 4.186 J/g°C Q=mc∆T
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How much energy is required to heat 250 grams of water from 20.0°C to 80.0°C? The heat capacity of water is 4.186 J/g°C

Q=mc∆T

User Koen Hendrikx
by
5.1k points

1 Answer

4 votes

Answer:

62,790J

Step-by-step explanation:

Q=mcT

= 250g*4.186J/gc*80-20

=250*4.186*60=62,790J

User Toro
by
4.8k points
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