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3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and the density of lead is 11.3 g/cm3, what is the mass of the apron in grams?

User M Arfan
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1 Answer

2 votes

Answer:

4.67 kg

Step-by-step explanation:

Given data

  • Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm
  • Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.


V = 75.0 cm * 55.0 cm * 0.10 cm = 413 cm^(3)

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.


\rho = (m)/(V) \\m = \rho * V = (11.3g)/(cm^(3) ) * 413cm^(3) = 4.67 * 10^(3) g = 4.67 kg

User Reddi
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