Question

6i4+6i3−2i2+−49−−−−√ rewritten in a+bi form

Answer 1

`8+i`

Explanation:

We are given that an expression

`6i^4+6i^3-2i^2+√(-49)`

We have to rewrite in the form of a+bi

`6(i^2)^2+6i^3-2i^2+√(-49)`

We know that

`i^2=-1`

`i^3=-i`

`√(-1)=i`

Using the identity

Then, we get

`6-6i-2(-1)+7i`

`(6+2)+(7-6)i`

`8+i`

This is required form of a+ib