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4 votes
Sin65°cos25 °+sin25 °cos65 °​

User Inshan
by
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1 Answer

0 votes

Answer:


sin(65\º)cos(25\º) + sin(25\º)cos(65\º) = sin(65\º + 25\º) = sin(90\º) = \sin{(\pi)/(2)} = 1

Explanation:

We use trigonometric identities to solve this question:


sin(A + B) = sin(A)cos(B) + sin(B)cos(A)

In this problem:

We have the right side of the equality, that is:


sin(65\º)cos(25\º) + sin(25\º)cos(65\º) = sin(A)cos(B) + sin(B)cos(A)

Which means that
A = 65\º, B = 25\º

Then


sin(65\º)cos(25\º) + sin(25\º)cos(65\º) = sin(65\º + 25\º) = sin(90\º) = \sin{(\pi)/(2)} = 1

User Panos Boc
by
8.4k points

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