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Num chuveiro ligado nas posições verão e inverno, com as seguintes características: 220V – 2200W/4400W. Calcule a corrente elétrica que circula na potência menor (verão) e maior (inverno), com a mesma tensão. Dica: isole a corrente elétrica na expressão P= i x U

User OldTroll
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Step-by-step explanation:

Let us assume that the question says,"In a shower connected in summer and winter positions, with the following characteristics: 220V - 2200W / 4400W. Calculate the electric current that circulates at the lowest (summer) and highest (winter) power, with the same voltage. Tip: isolate the electric current in the expression P = Ix V "

It is given that,

In a shower connected in summer and winter positions, with the following characteristics: 220 V - 2200 W / 4400 W.

It means lowest power is 2200 W and highest power is 4400 W

For lowest power,


P=VI

I = electric current for summer


I=(P)/(V)\\\\I=(2200)/(220)\\\\I=10\ A

For highest power,


P'=VI'

I' = electric current for winters


I'=(P)/(V)\\\\I'=(4400)/(220)\\\\I'=20\ A

User Gpbaculio
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