If (x + y)^2 = 1 and xy = -4, what is the value of x^2 + y^2?

asked Nov 5, 2021 77.2k views

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5 votes

Answer:

$(x + y)^(2) = 1\\xy = -4\\x^(2) + y^(2) \\= x^(2) + 2xy + y^(2) - 2xy \\= (x^(2) + 2xy + y^(2)) - 2xy\\= (x+y)^(2) - 2xy\\= 1 - 2 *(-4) \\= 9$

Hope this helps!

Justin Love answered Nov 9, 2021

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