F(n)=10*2^n at n=5 please show step by step on how you got the answer

asked Jan 16, 2021 218k views

3 votes

F(n)=10*2^n at n=5
please show step by step on how you got the answer

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6 votes

Answer:320

Step-by-step explanation:PEMDAS. So first you would do the exponent 2^5= 32 (2x2=4 4x2=8 8x2=16 16x2=32)

Then you multiply 10x32 which equals 320

Prk answered Jan 23, 2021

by Prk

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