F(n)=10*2^n at n=5 please show step by step on how you got the answer

Question

asked Jan 16, 2021 218k views

1 Answer

Prk · Answer 1 · 2021-01-23T02:58:04+0000

Answer:320

Step-by-step explanation:PEMDAS. So first you would do the exponent 2^5= 32 (2x2=4 4x2=8 8x2=16 16x2=32)

Then you multiply 10x32 which equals 320