Question

How would you solve dy/dx = 4x - 2, y(-1) = 1 using differential equations?

Answer 1

y=2(x square)-2x-3

Explanation:

Let dy with y varibles in a hand

And dx with x variables on the other hand

dy=(4x-2)dx

Then by integration

y=2(square x)-2x+constant

Then substitute by x=-1 and y=1 to find the value of the constant

1=2(1)-2(-1)+ constant

Then constant=-3

Then the equation is

y=2(x square)-2x-3