178k views
3 votes
The point (-3,2) lies on a circle whose equation is (x + 3)^2 + (y + 1 )^2 =r^2. Which of the following must be the radius of the circle?

The point (-3,2) lies on a circle whose equation is (x + 3)^2 + (y + 1 )^2 =r^2. Which-example-1
User Fqxp
by
7.5k points

1 Answer

3 votes

Answer:

1. 3

2. A

Explanation:

1. (-3+3)^2 + (2 + 1)^2 - r^2 = 0

0 + 9 - r^2 = 0

r^2 = 9

r = 3

2. 2x^2 + 4x + 2y^2 + 12y = - 6

Divide by 2.

(x^2 + 2x) + (y + 6y) = -3

Remember how to complete the square..

(b/2)^2

So...

(2/2) ^ 2 = 1

(6/2) ^ 2 = 9

(x^2 + 2x + 1) + (y^2 + 6y + 9) = -3 + 1 + 9 <--- You must remember to add whatever you add on the left to the right!

Now.. rewrite in standard form..

(x+1)^2 + (y+3)^2 = 7

Careful!! the circle equation is written as

(x - h)^2 + (y - h)^2 = r^2

Meaning that the radius is square root of 7. At center (-1, -3)

User Wesley Cheek
by
7.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories