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What are the solutions of 2x^2 +16+34=0?

User GalAbra
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1 Answer

4 votes

Answer:

5i, and - 5i ⇒ ± 5i

Explanation:

We are given the equation 2x^2 + 16 + 34 = 0;

2x^2 + 16 + 34 = 0 ⇒ subtract ( 16 + 34 ) from either side of equation,

2x^2 = - 50 ⇒ divide either side by 2,

x^2 = - 25 ⇒ take square root on either side of equation,

| x | = √ - 25 ⇒ apply imaginary value i,

± 5i, provided absolute value sign | |;

Solution; ± 5i

User Arlet
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