Question

What are the coordinates of the vertex of the parabola described by the equation below? y=7(x+5)^2-4

Answer 1

`y= 7(x+5)^2 -4`

The vertex form for a parabola is given by this expression:

`y = a(x-h)^2 +k`

By direct comparison we see that for this case:

`a = 7, h = -5 and k=-4`

And we know from the general expression that the vertex is:

`V= (h,k)`

So then the vertex for this case is:

`V= (-5,-4)`

Explanation:

For this case we have the following function:

`y= 7(x+5)^2 -4`

And we need to take in count that the vertex form for a parabola is given by this expression:

`y = a(x-h)^2 +k`

By direct comparison we see that for this case:

`a = 7, h = -5 and k=-4`

And we know from the general expression that the vertex is:

`V= (h,k)`

So then the vertex for this case is:

`V= (-5,-4)`