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A car starts its motion from rest and accelerates with an acceleration of 3m/s2 speed reaches to 20.0m/sec. Find time interval during this motion.

User Bluekeys
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1 Answer

5 votes

Answer:

The time interval is
t = 6.667 \ s

Step-by-step explanation:

From the question we are told that

The acceleration of the car is
a = 3 m/s^2

The velocity of the car is
v= 20.0 \ m/s

The final velocity of the car can be mathematically represented as


v =u + at

Now since the car start from rest u = 0 So


v = 0 + at


v = at

substituting values


20 = 3 t


t = (20)/(3)


t = 6.667 \ s

User JRJurman
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3.6k points