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The position of an object with respect to time, moving along the x-axis is given by x = b t3. Calculate the acceleration of the object if b = 3 m/s3.

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Answer:

The acceleration of the object measured in
(m)/(s^(2)), as a function of time is equal to:


a = 18\cdot t

Step-by-step explanation:

The acceleration function is obtained by deriving position function twice:


a = (dv)/(dt) = (d^(2)x)/(dt^(2))


x = 3\cdot t^(3)


v = 9 \cdot t^(2)


a = 18\cdot t

The acceleration of the object, measured in
(m)/(s^(2)), as a function of time is equal to:


a = 18\cdot t

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