Question

If an object is thrown upward from a 100-foot-high platform with an initial velocity of 64 feet

per second, then its height in feet is given by h(t) = -16t2 + 64t + 100 where t is time in
seconds. What is the maximum height reached by the object?

Answer 1

164 ft

Explanation:

The TIME of maximum height (this is a dome shaped parabola)

will be given by t = -b/2a = - 64 / (2)(-16) = 2 sec

Putting in t = 2 into the equation will give the max height

-16 (2^2) + 64(2) + 100 = max = 164 ft