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What is the equation of a line that passes through points (0, 4) and (-4, -8)? y = 2x + 4 y = 2x - 4 y = 3x + 4 y = 3x - 4

User Hyra
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1 Answer

2 votes

Answer:

y= 3x +4

Explanation:

The equation of a line is usually written in the form of y=mx +c, where m is the gradient and c is the y-intercept.

To find the value of m, use the gradient formula below:


gradient = (y1 - y2)/(x1 - x2)

Gradient


= (4 - ( - 8))/(0 - ( - 4)) \\ = (4 + 8)/(0 + 4) \\ = (12)/(4) \\ = 3

Subst. m=3 into the equation.

y= 3x +c

To find the value of c, substitute a coordinate.

When x=0, y=4,

4= 3(0) +c

c=4

Thus, the equation of the line is y= 3x +4.

User Garland
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