Question

On a coordinate plane, trapezoid A B C D has points (negative 3, negative 2), (negative 1, 2), (3, 2), and (5, negative 2). Trapezoid ABCD is graphed in a coordinate plane. What is the area of the trapezoid? 16 square units 24 square units 32 square units 48 square units

Answer 1

Its B

Explanation:

Answer 2

Correct option: second one -> 24 square units

Explanation:

First we need to find the length of each side of the trapezoid, and we do that finding the distance between points:

AB = sqrt( (-1 - (-3))^2 + (2 - (-2))^2) = 4.4721

BC = sqrt( (3 - (-1))^2 + (2 - 2)^2) = 4

CD = sqrt( (5 - 3)^2 + (-2 - 2)^2) = 4.4721

DA = sqrt( (-3 - 5)^2 + (-2 - (-2))^2) = 8

The points B and C have the same y-coordinate, and the points D and A also have the same y-coordinate, so they are the bases of the trapezoid.

The height of the trapezoid is the difference in y-coordinate of points B and A:

height = 2 - (-2) = 4

So the area of the trapezoid is:

Area = (BC + DA) * 4 / 2 = (4 + 8) * 2 = 24 square units

Correct option: second one