Question

The Anderson family has 3 kids 3 boys and 0 girls suppose that for each birth the probability of a boy birthday is 1/2 and the probability of a girl birth is also 1/2 what is the fractional probility of having 3 boys and 0 girls ina family first 3 births

Answer 1

Fractional probability of having 3 boys and 0 girls in a family for first 3 births is
`(1)/(8)`.

Explanation:

Let A be the event of birth of a boy.

Let B be the event of birth of a girl.

Probability of birth of a boy, P(A)
`= (1)/(2)`

Probability of birth of a girl, P(B)
`= (1)/(2)`

We have to find the probability of birth of 3 boys i.e. event A occurring 3 times in a succession. It is independent events i.e. do not have any dependency on occurrence of any event.

So, Required probability can be calculated just by multiplying P(A) for 3 times.

i.e.

`P(E) = P(A) * P(A) * P(A)\\\Rightarrow (1)/(2) * (1)/(2) * (1)/(2)\\\Rightarrow (1)/(8)`

So, the probability of having 3 boys and 0 girls in the family is
`(1)/(8)`.