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A box is pulled to the right with a force of 65 n at an angle of 58 degrees to the horizontal the surface of frictional is the Freebody diagram shown what is the net force of the X direction

User Rebelliard
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1 Answer

3 votes

Answer:

The force acting in x direction is 34.44 N

Step-by-step explanation:

We have,

Force acting on the box is 65 N at an angle of 58 degrees to the horizontal the surface of frictional.

It is required to find the net force in x- direction.

The net force acting in the x- direction is given by :


F_x=F\cos\theta\\\\F_x=65* \cos(58)\\\\F_x=34.44\ N

So, the force acting in x direction is 34.44 N.

User Zlaja
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