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2 votes
Including Jose, there are eight people in his family.

If order matters, how many ways can he arrange his family members into a row of five seats if Jose must sit in the first seat?
O 35
O 840
O 1,680
0 2,620

User Belal
by
5.2k points

2 Answers

1 vote

Answer:

The answer is B on Edge 2020

Explanation:

I did the Exam

User Farzana
by
5.8k points
2 votes

Answer:

840

Explanation:

Since the order matters, we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:


P_((n,x)) = (n!)/((n-x)!)

In this question:

The first seat is Jose's.

The remaining four are organized among the other 7 members. So


P_((7,4)) = (7!)/((7-4)!) = 840

So the correct answer is:

840

User Atomocopter
by
5.6k points