3.4k views
2 votes
What’s the correct answer for this?

What’s the correct answer for this?-example-1
User Ramone
by
8.3k points

2 Answers

2 votes

Answer:

First option is the correct answer

The equation of the circle is:
(x-6)^2+(y-4)^2= 25

The center is at (6, 4), and the radius is 5 units.

Explanation:


x^(2) -12x+27=-y^2 +8y\\\\x^(2) -12x+27+y^2 -8y=0\\(x^(2) -12x+36)-36+27+(y^2 -8y +16)-16=0\\(x^(2) -12x+6^2)+(y^2 -8y +4^2)-25=0\\(x-6)^2+(y-4)^2= 25\\(x-6)^2+(y-4)^2= 5^2\\Equating\: it \: with\\(x-h)^2+(y-k)^2= r^2\\we\:find:\\Center = (h,\:k) = (6,\:4)\\Radius \:(r) = 5

User JJ Roman
by
8.2k points
4 votes

Answer:

Explanation:

Bring to one side

x^2-12x+y^2-8y+27=0

Complete the square

(x^2-12x+A)+(y^2-8y+B)=-27

What’s the correct answer for this?-example-1
User Patrick Freitas
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories