Question

Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?

Answer 1

`C \approx 91.732^(\circ)`

Explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

`a = \sqrt{b^(2)+c^(2)-2\cdot b\cdot c \cdot \cos A}`

`a = \sqrt{5.79^(2)+10.4^(2)-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^(\circ)}`

`a \approx 8.466`

Finalmente, el angulo C se halla por medio de la misma ley:

`\cos C = - (c^(2)-a^(2)-b^(2))/(2\cdot a \cdot b)`

`\cos C = -(10.4^(2)-8.466^(2)-5.79^(2))/(2\cdot (8.466)\cdot (5.79))`

`\cos C = -0.030`

`C \approx 91.732^(\circ)`