Answer:
![y=2x^2+8x+8](https://img.qammunity.org/2021/formulas/mathematics/college/sde25n2ezpaksalq5abm1fbrteok1ertf7.png)
Explanation:
Notice that we are looking for a quadratic function that has only one real solution for y=0, that is a unique point that touches the x-axis
We need therefore to look at the discriminant associated with all 4 equations constructed by equaling y to zero. We then try to find one that gives discriminant zero , corresponding to a unique real solution to the equation.
a)
has discriminant:
![6^2-4(9)(4)=-108](https://img.qammunity.org/2021/formulas/mathematics/college/x4kff1fr2domp5esvw6y955i0ha29gy2e1.png)
b)
has discriminant:
![(-12)^2-4(6)(-6)=288](https://img.qammunity.org/2021/formulas/mathematics/college/mbqeapv39mdxo2m8ft0a2zhdbzj6wios7d.png)
c)
has discriminant:
![(7)^2-4(3)(5)=-11](https://img.qammunity.org/2021/formulas/mathematics/college/c6iofrzhyolrhtthnkro2hbe5f737mqkwe.png)
d)
has discriminant:
![(8)^2-4(2)(8)=0](https://img.qammunity.org/2021/formulas/mathematics/college/ep5air54qqs3o8o3zzbwfltowa84rsb9dn.png)
Therefore, the last function is the one that can have such graph