209k views
0 votes
A child in an inner tube is bobbing up and down in the ocean and notices that after a wave crest passes, four more crests pass in a time of 38.4 s and the distance between the crests is 32 m. If possible, determine the following properties for the wave. (If not possible, enter IMPOSSIBLE.)(a) Period (s)(b) Frequency (Hz)(c) Wavelength (m)(d) Speed ( m/s)(e) Amplitude (m)

User Sinval
by
5.6k points

1 Answer

0 votes

Answer:

Step-by-step explanation:

Given:

Four more crests pass in a time of 38.4 s and the distance between the crests is 32 m.

We have to determine five terms.

Lets start with one-one basis.

a.

Period = Time taken by a wave to pass though.


P = (Total\ time)/(No.\ of\ waves)


P = (38.4)/(4)


P=9.6 s

b.

Frequency = Reciprocal of time period in Hertz.


f=(1)/(T)


f=(1)/(9.6)


f=0.104 Hertz

c)

Wavelength = Distance between two consecutive trough and crest.


\lambda = 32 m

d.

Speed (v) = Product of frequency and wavelength.


v=f* \lambda


v=0.104* 32


v = 3.33 ms^-1

e)

Amplitude = The maximum displacement or half the distance from crest to trough.

⇒ Here it can't be determined.

⇒ Impossible.

User Davy M
by
5.8k points