Answer:
Step-by-step explanation:
Given:
Four more crests pass in a time of 38.4 s and the distance between the crests is 32 m.
We have to determine five terms.
Lets start with one-one basis.
a.
Period = Time taken by a wave to pass though.
⇒

⇒

⇒

b.
Frequency = Reciprocal of time period in Hertz.
⇒

⇒

⇒

c)
Wavelength = Distance between two consecutive trough and crest.
⇒

d.
Speed (v) = Product of frequency and wavelength.
⇒

⇒

⇒

e)
Amplitude = The maximum displacement or half the distance from crest to trough.
⇒ Here it can't be determined.
⇒ Impossible.