61.9k views
5 votes
Find the relative minimum of y = 3x^3 + 12x^2 - 10x - 56

(___, __)

Round your answers to the nearest tenth​

User Kalliopi
by
7.4k points

1 Answer

5 votes

Answer:

(0.4, -57.9)

Explanation:

y = 3x³ + 12x² - 10x - 56

dy/dx = 9x² + 24x - 10 = 0

x = [-24 +/- sqrt(24² - 4(9)(-10))]/(2×9)

x = -3.033006505, 0.3663398379

d²y/dx² = 18x + 24

For minima, d²y/dx² > 0 which is at x = 0.3663398379

y = 3(0.3663398379)³ + 12(0.3663398379)² - 10(0.3663398379) - 56

y = -57.90544608

User Laraconda
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories